Three-Phase Power and Current Calculator

Calculate apparent power (kVA) and current (A) in a three-phase system. Essential for sizing electrical equipment and ensuring system safety.

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🔧 Input Parameters

All values in engineering units

✅ Results

📜 Engineering Summary

Purpose
Three-Phase Power and Current Calculator
Standard
Category
Engineering
Applications
Commercial / Industrial / Residential

📥 Engineering Deliverables

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Frequently Asked Questions

What is the difference between apparent power (VA), real power (W), and reactive power (VAR)?
Real power (W/kW) is the power that actually performs work and produces heat. Reactive power (VAR/kVAR) circulates between the source and inductive loads (motors, transformers) without performing work — it sustains magnetic fields. Apparent power (VA/kVA) is the vector sum: S = √(P^2 + Q^2). Power factor = P/S = cos(φ). A PF of 0.85 lagging means 85% of the apparent current does real work; 15% circulates reactively.
Why does three-phase power use √3 in the formulas?
The √3 factor (1.732) appears because three-phase power is derived from the geometric relationship between line voltages and phase voltages in a balanced wye or delta system. In a wye system: V_LL = √3 * V_LN. In balanced conditions, total three-phase power P = 3 * V_PH * I_PH * cos(φ) = √3 * V_LL * I_L * cos(φ). This single √3 replaces the 3 * (√3) that would otherwise appear.
How does power factor affect three-phase current draw?
Current at constant real power: I = P / (√3 * V * PF). At PF=1.0 (purely resistive), current is minimum. At PF=0.7, current increases by 1/0.7 = 1.43x for the same kW. At PF=0.85, current is 1/0.85 = 1.18x the PF=1.0 value. Utilities charge for low PF because it increases line current and I^2R losses without delivering proportional real power.
What is the relationship between kW, kVA, and kVAR in three-phase?
The power triangle: P (adjacent) + jQ (perpendicular) = S (hypotenuse). Mathematically: S(kVA) = √(P^2 + Q^2), PF = P/S, Q = S * sin(arccos(PF)). Example: 100kW load at PF=0.80 → S = 100/0.80 = 125kVA, Q = 125 * sin(arccos(0.80)) = 125 * 0.6 = 75kVAR.
How do I calculate three-phase current from kW consumption?
Three-phase current from kW: I = P(kW) * 1000 / (√3 * V_LL * PF). Example: 50kW, 480V, PF=0.87 → I = 50,000 / (1.732 * 480 * 0.87) = 69.4A. This is the line current in each conductor. For unbalanced loads, calculate each phase separately using the phase voltage.
What causes low power factor and how is it corrected?
Low PF is caused by inductive loads: AC motors (especially lightly loaded), transformers, HID lighting, and VFDs without input reactors. Correction uses capacitors (capacitors supply reactive power, reducing Q from the source). PF correction should not over-correct to leading PF. IEEE519 limits total harmonic distortion, which capacitors alone cannot address — use harmonic filters for non-linear loads.